Why do you need to use the floating point routines in the first place?Originally Posted by iw2fvo
I don't really see a need for them in that code...
|
Why do you need to use the floating point routines in the first place?
I don't really see a need for them in that code...
|
It looks like your bin_bcd routine was writen for a 16F part. RLF is not an 18F instruction.
The 18F equivalent would be RLCF.
Also FSR and INDF are different on the 18F parts. You have FSR0, FSR1, FSR2, and INDF0,
INDF1, INDF2. See the 18F data sheet for details. You'll need to make a few changes to
compile this for an 18F.
Your example compiles fine with these changes to bin_bcd;
I can't say if it works or not, but it does compile without a single error.Code:bin_bcd: asm ;****************************************************************** ; Convert 32-bit binary number at <bin> into a bcd number ; at <bcd>. Uses Mike Keitz's procedure for handling bcd ; adjust; Modified Microchip AN526 for 32-bits. b2bcd movlw 32 ; 32-bits movwf _ii ; make cycle counter clrf _bcd ; clear result area clrf _bcd+1 clrf _bcd+2 clrf _bcd+3 clrf _bcd+4 b2bcd2 movlw _bcd ; make pointer movwf fsr0 movlw 5 movwf _cnt ; Mike's routine: b2bcd3 movlw 0x33 addwf indf0,f ; add to both nybbles btfsc indf0,3 ; test if low result > 7 andlw 0xf0 ; low result >7 so take the 3 out btfsc indf0,7 ; test if high result > 7 andlw 0x0f ; high result > 7 so ok subwf indf0,f ; any results <= 7, subtract back incf fsr0,f ; point to next decfsz _cnt goto b2bcd3 rlcf _binary+3,f ; get another bit rlcf _binary+2,f rlcf _binary+1,f rlcf _binary+0,f rlcf _bcd+4,f ; put it into bcd rlcf _bcd+3,f rlcf _bcd+2,f rlcf _bcd+1,f rlcf _bcd+0,f decfsz _ii,f ; all done? goto b2bcd2 ; no, loop ; yes endasm return
|
Mpasm and Melabs F P
Bruce,
your reply is a very good solution for the compiling errors.
As you point out the program compiles with NO errors.
That is great ! Thanks a lot for the help.
I will run the program on the 542 to see if it will work.
Bye
Ambrogio
IW2FVO
North Italy
|
mpasm and Melabs f p
Hi,
I am happy because I understand that you have read the basic program but I am really interested in knowing how can my program be wtitten without using the F P.
Could you please inform how it can be done ? It will be a very interesting solution.
Thanks for the help
regards,
Ambrogio
iw2fvo
Italy
|
Nothing interesting about it.
Where is the program using numbers between 0 and 1? Or fractions for that matter?
All I see is numbers that go above 16 bit. If that's the case, and you are using an 18Fxxx part, then you can use LONG variables to handle 32 bit (large) numbers.
|
|
mpasm and Melabs F P
Ok , Thanks Bruce I will have a look to longs as suggested.
I am writing a program in order to control the Analog Device AD9912 DDS: this device will be used as a RF signal generator for radio ham use. The point is that I have to multiply a number as like as
2^48/1000000000 ( 281474.976711) by another number that is the readout of the real output frequency ( from 1 Hz to 400 MHz ) . At the moment the Melabs FP works well and gives me the correct output frequency.
Unfortunately i can not put the " DDS" piece of program in a subroutine : in this case i do have no errors after compiling but the 16F877 does not work.
And, if I recall the "DDS" piece of program more than three times in my program i do have the same result.
>> question: how can i set the HS oscillator using the Mpasm and pic16f877 with no problem ?
Thanks a lot.
Ambrogio
IW2FVO
|
Would've been a lot handier to have that information awhile back ya think?
Now I see what you're trying to do. I suppose it's a matter of how you look at it. You need the ability to handle large numbers more than you need floating point specifically...and to be able to handle those numbers with some precision. If I remember right, PBP can handle some 48 bit math (more specifically, I think you can retrieve some of the overflow from a 32x32 multiply). I don't have the manual handy, so I don't want to comment on it at the moment.
|
|
mpasm long ... /... fp
Hi,
is the picbasic pro manual " 3 / 04" applicable to the 2.50 version of PBP ?
Tnks
Bye
Ambrogio
IW2FVO
|
mpasm and melabs F P
Hi,
thanks for the interest:
this is the peace of program that in my opinion needs a fp:
'DDS: '------------------------------------------------------------------------
AARGB0=f0
AARGB1=f1
AARGB2=f2
AARGB3=f3
ASM
CALL flo3232
ENDASM
debug HEX2 f0," ", HEX2 f1," ", HEX2 f2, " " , HEX2 f3, 13,10
' CALCOLO DELLA FTW DA INVIARE AL DDS
' 2^48/1.000.000.000= 281474,976710656
' USARE IL PROGRAMMA FREP.EXE DELLE ROUTINES FP PER CONVERTIRLO DIRETTAMENTE
' ATTENZIONE: USARE $81 INVECE DI 91 PERCHE' I 2 BYTE MENO SIGNUFICATIVI LI LASCIO
' A ZERO ( VEDERE MAIL DI i0cg )
BEXP=$81
BARGB0=$09
BARGB1=$70
BARGB2=$5F
GOSUB FPMUL
ASM
CALL INT3232
ENDASM
'debug " start ",dec aargb0," ",dec aargb1," ", dec aargb2," ",dec aargb3,13,10
LOW DDSCSB
'SHIFTOUT DDSDAT,DDSCLK,1,[%01100001,%10101011,aargb0,aargb1,aargb2,aargb3,$0 0,$00]
HIGH DDSCSB
HIGH DDSUPDT
LOW DDSUPDT
-------------------------------------------------------------------------------------
Have you some differents indication for me ?
( I am sorry for my bad English .. I am Italian )
Sometimes is very hard for me to understand the real meaning of the things !
Thanks again
Ambrogio
IW2FVO
|
Why does it need floating point?
Just because the program has it there, doesn't mean it has to be there.
Rewrite the program to NOT use floating point.
Again, I don't see any decimals points needed here. At most, a 32 bit variable.
Members who have read this thread : 0You do not have permission to view the list of names.
Posting Permissions
Bookmarks