Choosing a transistor


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  1. #1
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    I had a look for that book. £48.45 on Amazon! It wants to be good for that price. Ill add it to my x-mas list

    The LEDs im looking at are 15 degrees i guess that puts them towards the dimmer end.

    So, using LEDs on 12V in parallel is definately out of the question. Looks like ill be using a series-parallel type circuit. That way each of the 4 sets of LEDs should only use 200mA of current.

    If i only need 200mA now is it still better to use a mosfet instead of an NPN transistor? Yes i can use NPN now with these other LEDs

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    Luciano, I have seen the max forward voltage. I thought it meant on average.

    Im using more LEDs now. Ive re-arranged the circuit a little so that theres hardly even room for the 2 screws and ive got 48 LEDs on it. Its a bit less cramped on the track side because each LED only has 2 legs instead of 6. There are 12 LEDs in each color. The datasheet says 4.2V max for the white ones. If i have groups of them in parrallel (4 LEDs in each group) and connect the groups in series then i should end up with 4V per LED. I think that means they would only use 150mA per color too

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    Dave
    Always wear safety glasses while programming.

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    Hi,

    The power dissipated in a MOSFET is the voltage across it times
    the current going through it.

    The voltage across the MOSFET when it is on will be the
    resistance of the MOSFET, Rds(on) times the current going
    thorough it.

    A MOSFET IRLR/U2905 has a on-resistance of 0.027Ω.

    Power dissipated by the MOSFET case when you have 2 Amps of
    current going thorough it will be: (2A = 100 LED's 20mA).

    P = 2A^2 * 0.027Ω = 0.108 Watts.

    (No problem without heatsink).

    Best regards,

    Luciano

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    Quote Originally Posted by Luciano View Post
    (No problem without heatsink).
    Thats good news then. I dont even have room for TO220 packages. Theres no way i could get a heatsink to fit in there. Im not even using a heatsink for my voltage regulator since it never gets remotely warm with just a PIC chip and a MAX485 connected.

    One thing i dont understand is how you know that 0.108W means you dont need a heatsink

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    Quote Originally Posted by The Master View Post
    One thing i dont understand is how you know that 0.108W means you dont need a heatsink
    Hi,

    From the datasheet. The thermal resistance junction-to-ambient is for when
    there is no heatsink.

    IRLR/U2905 datasheet:
    http://www.irf.com/product-info/data...a/irlr2905.pdf

    The thermal resistance Junction-to-Ambient of an IRLR2905 is 110 °C/W.
    Its operating junction temperature range is -55 to + 175 °C.


    Code:
    Example ambient air temperature = 45°C: 
    
    175°C − 45°C
    __________    =  1.18 Watts 
       110°C/W
    
    With an ambient air temperature of 45°C, without 
    heatsink an IRLR2905 can dissipate 1.18 Watts. (Absolute Maximum).

    Best regards,

    Luciano
    Last edited by Luciano; - 30th September 2008 at 17:35.

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    Quote Originally Posted by Luciano View Post
    The voltage across the MOSFET when it is on will be the
    resistance of the MOSFET, Rds(on) times the current going
    thorough it.
    A MOSFET IRLR/U2905 has a on-resistance of 0.027Ω.
    Of course that also assumes you are driving the MOSFET 'hard enough' (i.e. large enough Vgs vs. Vds) to get that low Rds(on).
    If you come up a bit short on the Vgs, the Rds(on) could be much higher.

    It's always something, ain't it?

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    Quote Originally Posted by skimask View Post
    Of course that also assumes you are driving the MOSFET 'hard enough' (i.e. large enough Vgs vs. Vds) to get that low Rds(on).
    If you come up a bit short on the Vgs, the Rds(on) could be much higher.

    It's always something, ain't it?
    The power MOSFET IRLR/U2905 has logic-level gate drive and
    therefore you don’t have to worry about that. Just try and
    measure the voltage drop.
    Last edited by Luciano; - 30th September 2008 at 18:39.

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    Ive been looking at the datasheets again and as far as i can see the LEDs in total will use at most 200mA per color. Ive been trying to find a suitable mosfet to control them but im still having a bit of trouble. There is a category on rapid called "TO-220 Logic level power MOSFETs N-Channel". I dont want a TO220 package but i thought i would look at the datasheets anyway because they seem to be exactly what you recommended. I still cant seem to understand this gate voltage. Even the logic level one im looking at says "Gate-source voltage ±18V". There is also a "Gate Threshold Voltage" That says 2.5V. Is that what i should be looking at?

    I almost got the heatsink bit. skimask confused me a bit though. I have a rough idea of how hot certain components will get with a certain load on them but usually i just put my finger on it to test. That seems to work well except for when i shorted a regulator out once... ouch :P

    So, It looks like the only logic level mosfets that rapid do are in a TO220 package. I want to look through the rest of the mosfets to see if any will do the job but it looks like most of them are for audio circuits

    Edit: Would the 2N7000 N CHANNEL MOSFET be suitable?
    Last edited by The Master; - 30th September 2008 at 22:44.

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    Yes that is usefull. I think im using the type of regulators they mentioned (the bad ones). The plan was to use a 12V one for the LEDs and a 5V one for the rest of the circuit. It will help picking the correct resistors for the different colors too (each color uses different amounts of amps and volts)

    The lights im making are actually like spotlights so i would have thought a 15 degree angle should be fine. There is a directivity diagram in the datasheet Im not sure if thats what you mean. I can try and compare it with some other LEDs i already have but the best thing is probably to buy a few and turn them on

    I do have a multimeter and now a PC oscilloscope. I had to use them a lot while getting a test circuit working with the origional multicolor LEDs

    I see what your saying about the transistors. I did have some running with the old LEDs though and they seemed to be fine. They did start getting a little hot so i turned my PSU down a little. They cooled back down and continued to run for about 2 hours with no noticable temperature increase. I will order some mosfets instead though just to be on the safe side.

    I think what im going to do is try to figure out exactly what mosfets and resistors i need etc for those LEDs then buy a few and see how they work

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    Quote Originally Posted by The Master View Post
    I had a look for that book. £48.45 on Amazon! It wants to be good for that price. Ill add it to my x-mas list
    Obviously, not everything in that book applies, but the first bunch of chapters (i.e. 1/3 of the book) breaks down the basics of transistors/mosfets, and the bulk of the discrete components needed to put together a complete circuit. And it really helps to have a few examples of each laying around, along with some spare parts and a meter (and/or 'scope) to play with pieces/parts and see what actually happens in practice vs. just reading all about it.

    The LEDs im looking at are 15 degrees i guess that puts them towards the dimmer end.
    Not necessarily. Look at the datasheets for those LEDs, look at the distribution, then compare that LED with the cheaper and more expensive types.

    If i only need 200mA now is it still better to use a mosfet instead of an NPN transistor? Yes i can use NPN now with these other LEDs
    I think you're better off using a MOSFET over a BJT anyday. The 'bible' mentioned above shows why and I don't remember exactly why. But it's got something to do with the forward bias voltage. A BJT gets hot, forward bias voltage drops a smidge, current flow rises, BJT gets hotter, forward bias voltage drops a smidge, current flow rises, it's a nasty circle of death for the BJT. With a MOSFET, it effectively chokes itself when it gets hot. I don't remember the exact mechanism by which this happens, but it supposedly can 'save itself' in certain situation whereas a BJT would go up in smoke.

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