Richard brings up an important point about the PIC's drive current capacity. I'll use 10mA in my calculations.
R = V / I
= 5 / 0.010
= 500
P = V * I
= 5 * 0.010
= 0.050 W (just...
That's a cool service. 😎
Gonna save that one.
Sometimes it is cheaper in small quantities to have someone make your parts vs building your machines to do the job. Plasma cutters do not make clean enough cuts as needed for control panels. Anyway...
mark_s - 24th July 2025, 16:40no gate driver needed for occasional intermittent switch... the rise and fall times are where there is power dissipated in the mosfet...... do a calculation of the power dissipated in that 30 micro...
amgen - 24th July 2025, 15:091 columb = 1 amp for 1 second
To apply 6nC of charge in 5.5 nanoseconds takes
6e-9/5.5e-9 = 1.09 amps
It needs a gate driver to get that speed, a pic with 20mA of drive can provide a 6nC...
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usually, all the gate drive circuits mostly have to do with the frequency the mosfet is engineered to operate. That is where high frequencies matter and the rise and fall times of the mosfet...
One of the challenges I had given myself was to simulate an electric breaker in MSFS, just like the ones in a Cessna 152.
9983
So far, the least expensive and "good enough" technique was...
Excellent!
Yeah, that's why I considered the opto-couplers at first; to isolate the solenoid from the 5V circuit, but I'll be using separate sources:
- 5V from TPS56637 (for PICs, LEDs, and all...
Using datasheet:
https://www.aosmd.com/res/datasheets/AO3400A.pdf
My work so far:
I added tD(ON) and tr to get total t
Google AI says:
Ig = Qg / t
Re: Calculating base resistor on mosfet AO3400A
You can drive the MosFet directly from PIC as your frequency of activations is really slow.
Ioannis Yesterday, 10:57Gate driver is needed if your frequency is high. Also resistors or ferrite beads are also neededin...