Division with some decimal

[Darklakebridge7]

Hi to everybody!

I would have the necessity to perform the following division in PIC Basic, but I don't know from how stings to depart.

A = B / 5,58

B is a constant

I would have the necessity to visualize the result on a display LCD also visualizing 2 decimal.

Can someone help me?

Thanks everybody

[skimask]

Hi to everybody! I would have the necessity to perform the following division in PIC Basic, but I don't know from how stings to depart.
A = B / 5,58 B is a constant
I would have the necessity to visualize the result on a display LCD also visualizing 2 decimal. Can someone help me? Thanks everybody

You do know that PBP does NOT deal with fractions and decimals...right?

a var word
b var word
'start with a number in b
1 - b = 655 ' maximum value in b is 655, otherwise word variable b will overflow
2 - b = b * 100 'shift the decimal point over to right 2 places temporarily
3 - a = b / 558 'constant value of 5.58 also has it's decimal point shifted over by 2 places

1 - b = 655 (given)
2 - b = 65500 (closest you can get without overflowing a word value)
3 - a = 117 ( 65500 / 558, PBP doesn't do fractions)

Do a search on 'decimal' and 'fraction' here and you'll find some stuff. Otherwise, download the floating point math routines from microchip if you need good accuracy.

[BigWumpus]

While B is a constant,
just type it to your desktop-calculator and place the result inside a LCDOUT-command. ;-)

Because, if B is a constant and 5,58 too - the result "A" is another constant. You don't need any calculation in runtime...

[skimask]

While B is a constant,
just type it to your desktop-calculator and place the result inside a LCDOUT-command. ;-)

Because, if B is a constant and 5,58 too - the result "A" is another constant. You don't need any calculation in runtime...

Oh..Hey...Good point!
Missed that entirely! DOH!
That really would save a lot of calculation time wouldn't it...

[Darklakebridge7]

Hi boys!

I have been wrong to expose the problem!

I would have the necessity to divide the variable "B" for the number 5,58 and subsequently to visualize the result "A" on LCD.

My very problem is the following:

A = B / 5,58

Excuse the error! Everybody can help me??

[rossfree]

Not knowing the size of B, I've used DIV32. B can be any integer up to 65534.

A VAR WORD
B VAR WORD


A = B * 100 'A is temporary storage of computation
A = DIV32 558 'using DIV32... B can be any integer up to 65534
A = A / 100 'final result is placed in variable A as an integer... any
'remainder will be discarded.

Hope this helps,

Ross

[Darrel Taylor]

A = B / 5,58

Now then, where were we?

Darklakebridge7,

An easy way to think about it is to look at how you would "Name" the numer.

For instance,

5.58 is 558 hundredth's of whatever it is.

So if you multiply by 558, then divide by 100 (hundredths), you end up with the correct answer. (integers only)

B = 123
A = B * 558
A = DIV32 100

Piece of Pie, or was that cake.

[Darklakebridge7]

Now then, where were we?

Darklakebridge7,

An easy way to think about it is to look at how you would "Name" the numer.

For instance,

5.58 is 558 hundredth's of whatever it is.

So if you multiply by 558, then divide by 100 (hundredths), you end up with the correct answer. (integers only)

B = 123
A = B * 558
A = DIV32 100

Piece of Pie, or was that cake.

Hi to everybody!

Forgive me, but I am new and I have some problem with the language English! Could you recommend me a some good book of PIC Basic?

A special thanks to all those people that have helped me to resolve my problem!

[mister_e]

No need for a book! Forum and head-banging is more than enough!

[rossfree]

A VAR WORD
B VAR WORD
TNTH VAR BYTE
HUNDTH VAR BYTE


A = B * 100 'A is temporary storage of computation
A = DIV32 558 'using DIV32... B can be any integer up to 65534
TNTH = A DIG 1 'GRAB THE "TENS" DIGIT FROM "A"
HUNDTH = A DIG 0 'GRAB THE "ONES" DIGIT FROM "A"
A = A / 100 'final result is placed in variable A as an integer... any 'remainder will be discarded.

LDCOUT $FE,1 'CLEAR DISPLAY
LCDOUT "A = ",#A,".",#TNTH,#HUNDTH

I think that would give you what you want.

Ross