Changing Swordfish code to PBP

[mackrackit]

Would a long addition of one to$7FFFFFFF, make $80000000

Yes, $7FFFFFFF= 22147483647 $80000000 = 2147483648

That is about as much help as I can give. But it does look like you will need to divide by 10000 or so to make the numbers workable.

[Ron Marcus]

Yes, $7FFFFFFF= 2147483647 $80000000 = 2147483648

That is about as much help as I can give. But it does look like you will need to divide by 10000 or so to make the numbers workable.

My belief is that when bit #31 is set, it becomes a negative number in the eyes of PBPL.So it would be -2147483647

[mackrackit]

You might be right, I am still learning this new stuff and I have a way of making it more confusing than it needs to be, I guess.

If it is -2147483647 then the hex would be $FF8000001 ??? Now I see why you asked about the carry.
Or if -2147483647 +1 = -2147483646 = $FF80000002 and the absolute value would be $7FFFFFFE

I will be quiet now