Write and Read from eeprom

[jason]

Its the internal eeprom of the pic16f84a

[skimask]

Its the internal eeprom of the pic16f84a

uhh...der...it sure is...dumb question on my part...


Break it down, get it simple, get rid of all of that other stuff in your program, make something seriously simple, and build it back up. There is a bit of a logic error in your program that'll probably cause your symptoms.

[jason]

Thank you for your quick help on this

Ok I did as you suggested

I made a new file, and slowly added until I had a problem. I'm not sure if this is the problem with my "write" but I wouldn't doubt it, due to some sort of overflow.

here I am trying to get a percentage of a word sized integer


percent=35
example: A=65535 * .35 or A=(65535*100) /35

'-----------
A = TOTAL * 100 'A is temporary storage of computation
A = DIV32 PERCENT 'using DIV32... B can be any integer up to 65534
'-----------

if total=100 wouldn't A=35 ???


I'm not familiar with DIV32 at all, I read up on it and understand somewhat how it works, becuase PBP can't deal with numbers larger than a "word" it uses this as a temperary variable so that people like me can do this type of math, right ?

[Acetronics2]

Hi, Jason

Did you had a look to THAT Thread ???

http://www.picbasic.co.uk/forum/showthread.php?t=1078

Alain

[jason]

WOW

I think that is my problem here. However I only understood a little bit of it.

Why is this so complicated just to store a word ?

OK, so I thought storing total.byte0 in location 0 and then storing total.byte1 in location 1 would handle the whole word right ?
'----------------------------------------------------------------------
total=33024 or total.byte0=10000000 and total.byte1=11111111
write 0,total.byte0
write 1,total.byte1

If so then in location 0 would be 10000000 and in location 1 would be 11111111
or is this wrong ?

if it is right then I can't get that data back the same way ?

read 0,total.byte0
read 1,total.byte1

total=33024

if not then what ???? I'm more confused then before, but I think your on the right track

[rhino]

total=33024
Binary(33024) = %1000000100000000
total.BYTE1 = %10000001
total.BYTE0 = %00000000

To write a word, each of the 2 bytes that make up the word must be
written separately:
w Var Word
WRITE 0,w.BYTE0
WRITE 1,w.BYTE1

[skimask]

And there be the logic error I thought I saw earlier...
Now build you program up and see what happens...then we can work on optimizing that program a bit. I looks a bit of a mess...not too bad, but could be better...

[jason]

thank you for setting me straight, however that didnt answer my question. am i reading the data back to "total" correctly ?