2 LEDs and one pin left

[mackrackit]

COOOL!!!!!

I can think of several places where that will come in handy.
Looks like it would make a good article for the wiki. Add a bit of code and schematic for basic use....

[muddy0409]

Tried this on my Breadboard, works a treat.
Hmmm....have to work out how to ad a JPG to this...
BRB


Ah, there it is, I hope. I know it means 2 extra LEDs, but that's gotta be cheaper than changing the PIC or messing around with the power supply.
With the pin as an input, the 5 volt rail is not enough to turn on any of the leds, but setting the pin Hi or Lo the voltage is enough to turn on 2 of them. Also no current drawn during the Input stage.

[Mike, K8LH]

Jumper,

What does the rest of your circuit look like?

Regards, Mike

[rsocor01]

Add a bit of code and schematic for basic use....

Ok.

I attached the schematics to this post. The code is pretty simple. It uses only one pin in the PIC to create four states in the red-green LED. You can get Red, Green, Yellow, or the Off state in the LED using only one pin. Of course, for getting the last state (Off) all the credit goes to mackrackit. He figured that one out .

START:

HIGH PORTB.0                 'Turn on red light
PAUSE 2000 

LOW PORTB.0                  'Turn on green light  
PAUSE 2000   

FOR I = 1 TO 2000            'Obtain a yellow light
   TOGGLE PORTB.0
   PAUSE 1
NEXT I

TRISB.0 = 1                  'Turn off LED
PAUSE 2000 
   
GOTO START

[Dave]

I vote for Muddy0409's except, I would put a resistor in series with the processor output lead to limit the output current. This is exactly what I would have proposed except I would have used a couple of zeners instead of the extra led in each leg... If you have an extra inverter available you could modulate one side of a bidirectional led (red/green) and connect the other side thru a resistor to the processor output pin and then place it either high or low and finally to an input state to shut it off.....

Dave Purola,
N8NTA

[cncmachineguy]

Referring to the attachment 2 posts above,

Am I just missing something? by my calcs, assuming 2V drop for the LED's the current would be 3/10000 = .3mA.

Will this be enough to light the LED? By my calcs, I would think 150-200 ohms would be more suitable. Any help to clear this up for me?

[Darrel Taylor]

I don't think the attachment 2 posts above will do any good with 10k resistors.

I had actually started making a flash demo for this when it first started, but with so many options it got too complicated.
I really think the correct theory is in the link from post #13 though. The link is also in the flash below ... under the title. (batsocks.co.uk/ ....)

I only made it through simulating +5V. Things are clickable in the image below ... try it.
At +5V the resistor is 100 ohms (with 2 diodes).
But if your situation is different, perhaps I can add to it. ...

<OBJECT CLASSID="clsid:D27CDB6E-AE6D-11cf-96B8-444553540000" CODEBASE="http://download.macromedia.com/pub/shockwave/cabs/flash/swflash.cab#version=6,0,40,0" WIDTH="723" HEIGHT="800" ><PARAM NAME="MOVIE" VALUE="http://www.pbpgroup.com/files/2LED/2LEDS_1PIN.swf"><PARAM NAME="PLAY" VALUE="true"><PARAM NAME="LOOP" VALUE="truSe"><PARAM NAME="QUALITY" VALUE="high"><EMBED SRC="http://www.pbpgroup.com/files/2LED/2LEDS_1PIN.swf" WIDTH="723" HEIGHT="800" PLAY="true" LOOP="true" WMODE="opaque" QUALITY="high" TYPE="application/x-shockwave-flash" PLUGINSPAGE="http://www.macromedia.com/go/getflashplayer"></EMBED></OBJECT>
Oh, it says I attached the .dsn file ... I didn't, cause it wasn't done.
But if you have Proteus, I will make it work for all conditions ...

[cncmachineguy]

Thanks Darrel. That is an awesome gadget. Is there any way to get you to replace d2 and d3 with variable resistors (or fixed if need be) and bypass the 200 ohm on the pin? This way it will be closer to the other circuit. I would love to test it (and yes, I am trying to use your sim instead of my breadboard) I think a more approiate value would be 0-1000 ohms. If not, its all good.

[Darrel Taylor]

Well, the problem with that ... is that the variable resistors would only control current.
But the correct operation of the LED's depends on the voltage.

If the total forward voltage of the LED's is less than VDD, both LED's will be ON no matter what the resistor values are. The only difference will be their brightness.

Given a specific VDD voltage, LED color (V forward) and foward current, the correct configuration can be found.

And to add 2 variable resistors to the flash demo, would increase the frames from ~50 to more than 500,000. I'm affraid that will take a few years to create, and you probably won't wait the 2 weeks to download it.
I suppose it could be done more efficiently.

But again, if you have Proteus, it's a "Piece of Cake".

[cncmachineguy]

thanks darrel, once again, it seems a case of I know not what I ask. Don't worry about the demo then. As for the actual circuit, I will have to mull over why the 2 resistors in series with the led's doesn't create a voltage divider.

I would just LOVE to have proteus. I tried looking it up 1 time, seems it was in the 4 digits, just a little much for me