Sorry, yet ANOTHER mod question

[richard]

14 mod 10 = 4 mod gives you the remainder after the division ie ten goes into 14 once with 4 leftover , its not what you want
frac = volts*10 mod 100 is what you want ie 1469 mod 100 = 69 but
the following is easier
forget the frac
volts_in = (volts_in * 10) / 498

try lcdout $fe, $c0, "voltage is: ", volts_in/100, ".", dec2 volts_in

[andywpg]

14 mod 10 = 4 mod gives you the remainder after the division ie ten goes into 14 once with 4 leftover , its not what you want
frac = volts*10 mod 100 is what you want ie 1469 mod 100 = 69 but
the following is easier
forget the frac
volts_in = (volts_in * 10) / 498

try lcdout $fe, $c0, "voltage is: ", volts_in/100, ".", dec2 volts_in

Hmmm, neither of those seemed to work for me - didn't get what I was looking for.

Then I tried this:

MEASURE_VOLTS:
	ADCIN 2, VOLTS_IN 'READ CURRENT VALUE OF INPUT VOLTAGE DIVIDER
	VOLTS_VAL = (VOLTS_IN * 10) / 498
	VOLTS_FRAC = (VOLTS_IN * 10)  MOD 100

	
	LCDOUT $FE, 1, "CURRENT INPUT"
	LCDOUT $FE, $C0,   "VOLTAGE IS: ", DEC2 VOLTS_VAL, ".", DEC2 VOLTS_FRAC

Still not right, so I modified the fraction line to: VOLTS_FRAC = ((VOLTS_IN * 10) / 498) MOD 100

But that gives me 14.14 - still not right. Any other ideas? And thanks again for the help

[richard]

got that wrong
frac = volts*1000/498 mod 100 is what you want ie 1469 mod 100 = 69 but it may cause overflows


volts_in = (volts_in * 100) / 498 (should be ok internal mult/div is 32 bit in pbp3 anyway)

try lcdout $fe, $c0, "voltage is: ", volts_in/10, ".", dec1 volts_in