assigning register bits to an array?

[jderson]

Alistair

After close examination and some digging, I find the LCD on this board (datasheet attached) is a 1/4 multiplexed display. This is done to keep the number of pins to a minimum, but boy, is it going to be fun to program! This is intriguing to me, because that infers I can use a 16f913 with this display.
Now all I have to do is find a place to buy it!

Dave

[bakerajatha]

from the link posted by joe s i did some digging around and i came accreoo this little gem from Ingvar

x var byte
i var byte

main:
for i = 0 to 3
' a b c d
' 0 6 4 2
LOOKUP i, [0,14,20,26], x
porta.0[x]=1
PAUSE 1000
porta.0[x]=0
PAUSE 300
next i


from this thread http://www.picbasic.co.uk/forum/showthread.php?t=4074

Which is using a look up table to (undocumented feature) offset address a port bit off a register. they are talking about relays but i'm going to have a go for lcddata register bit addressing

Thanks to all for your help

Alastair

[bakerajatha]

this works passing a bit pattern to individual bits as long as you know the bit offset from a register

in my case using register LCDDATA

' lcd setup
lcdcon = %11111111 'control register
lcdse0 = %11111111
lcdse1 = %11111111
lcdse2 = %11111111 'choose all pins for lcd use
lcdps = %00000000 'clock control, 0 is static


i var byte
x var byte
set var byte


main:
'display charactor '0' on 1st segment
for i= 0 to 6
lookup i, [22,23,71,94,70,46,47], x '1st 7-segments offsets
lookup i, [1,1,1,1,1,1,1,0],set 'set character '0'
LCDDATA0.0[x] = set 'display it
next i
pause 500 'some time to see it

'display charactor '4' on 1st segment
for i= 0 to 6
lookup i, [22,23,71,94,70,46,47],x '1st 7-segment
lookup i, [0,1,1,0,0,1,1],set 'set character '4'
LCDDATA0.0[x] = set 'display it
next i
pause 500 'some time to see it

goto main

-------------------------------------------------
With this my origional question answered, thanks to all

alastair