skimask;64450]Right. I understand what you are trying to do, with the EEPROM and the LED matrix's and such. It's a relatively common project.
What you aren't understanding is that you are only writing ONE BYTE at a time with those statements, not 3 at a time as your changing addresses would indicate.
And one other thing is 'precedence'. I'm not sure if it's applicable in this case, but...
In your statement above...
Code:
i2cwrite I2CDAT, I2CCLK, $A0, adr,[temperature.LOWBYTE dig 4+48 ]
How does that get interpreted?
Assume temperature.lowbyte = 123
You are trying to retrieve the 4th (actually 5th) digit of a byte value to which there can only be 3 digits.

I understand what you say , but I try something , to see what display

Another thing, still assuming temperature.lowbyte = 123, and assume that 'dig 4' is actually 'dig 0'...
Will that statement return "3" + 48 or does it try to return the 52nd digit of temperature.lowbyte?
A better way to put that statement might be:
Code:
i2cwrite I2CDAT, I2CCLK, $A0, adr,[ ( temperature.LOWBYTE dig 4 ) + 48 ]

Is not imprtant , + or - paranthesis I see on display the same result .

For the result of " temperature.LOWBYTE " I do not understand what is this number .
If I put

adr = 24
i2cwrite I2CDAT, I2CCLK, $A0, adr,[(temperature dig 2) + 48]
pause 15
adr = 27
i2cwrite I2CDAT, I2CCLK, $A0, adr,[(temperature dig 1) + 48]
pause 15
adr = 30
i2cwrite I2CDAT, I2CCLK, $A0, adr,[(temperature dig 0) + 48]
pause 15

Obtein a number which is a hexa from a teperature ...968 ,975 - 2408,2421
For a LCD display write DEC2 (temperature/100) "," DEC2 (temperature//100). But for me in this moment I do not know what to do !