Pretty much does, but you have to calculate the offset caused by the diode's forward voltage drop (either ~.25v or ~.6v depending on the type)
Series to ground, parallel across itself, whatever, you'll have to figure that out yourself (think R/C time constant). The bleed resistor will let the cap falls off if/when the input voltage average drops. I think you've got the idea, just need to plug some numbers into a couple formulas.What is the purpose of a "bleed" resistor? Is that to go in series or parallel with the capacitor?
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