A simple and basic question

[Ted's]

This is what is written in between

   48						LABEL?L	L00001	
     +					        LALL
     +	0019-				L00001
    49						CMPGE?WCL	_Zahl, 0EA60h, L00002
     +	0019- 0838			        movf    _Zahl, W
     +	001A- 00A0			        movwf   R0
     +	001B- 0839			        movf    (_Zahl) + 1, W
     +	001C- 00A1			        movwf   (R0) + 1
     +	001D- 30EA			        movlw   low ((0EA60h) >> 8)
     +	001E- 00A3			        movwf   R1 + 1
     +	001F- 3060			        movlw   low (low (0EA60h))
     +	0020- 2001			        call    CMPGE
     +	0021- 1D03			        btfss   STATUS, Z
     +	0022- 2827			        goto    L00002
    50						ADD?WCW	_Zahl, 001h, _Zahl
     +	0023- 0AB8			        incf    _Zahl, F
     +	0024- 1903			        btfsc   STATUS, Z
     +	0025- 0AB9			        incf    _Zahl + 1, F
    51						GOTO?L	L00001
     +	0026- 2819			        goto    L00001
    52						LABEL?L	L00002	
     +					        LALL
     +	0027-				L00002
    53

What is more, there is no question about my configuration. It is a timing issue. The osc value determines the speed to let the program know how many cycles one millisecond will take f.i.. Knowing the speed there is enough information to reproduce the question and to give an answer. I am not here to relearn what would take others just a few seconds to reproduce - less than writing a "do it yourself" takes.

I am going to use Jackson's 3us and this is the end of the story.

Do not make things more complicated than they have to be.