Is Number Odd?

[T.Jackson]

Is there more than one way to test to see if an integer is even or odd? So far I've only been abe to devise one solution. The solution makes use of the AND bitwise operator.

public boolean isNumOdd(int num)
{
   if (1 & num)
      return true;
   else
      return false;
}

PBP code ...

main:
   if 1 & num then
      oddNum = true
   else
      oddNum = false
   end if

Has anyone got another way of doing this? I'm incredibly keen to hear your thoughts.

Best Regards,

Trent Jackson

[Melanie]

	If num.0=1 then
		oddNum = true
		else
		oddNum = false
		endif

[sayzer]

GrandPa's way!

OddNum = True
IF Num // 2 = 0 THEN OddNum = False

Does Num = 1 work?
----------------------------

[T.Jackson]

OddNum = True
IF Num // 2 = 0 THEN OddNum = False

Do me a favour and refresh my memory with what "//" does?

Trent Jackson

[dhouston]

Page 32 of the PBP manual defines it as Remainder (Modulus). I believe Modulus or Modulo is the more generally used terminology. It's also more useful, generally, than the other methods suggested as you can use it to test whether any number is evenly divisible by any other number. See...

• http://en.wikipedia.org/wiki/Modulo_operation

[sayzer]

Page 32 of the PBP manual defines it as Remainder (Modulus). I believe Modulus is the more generally used terminology. It's also more useful, generally, as you can use it to test whether any number is evenly divisible by any other number.

Do me a favour and refresh my memory with what "//" does?

Trent Jackson

I knew it did something for sure; (well, at least at where I am it does).

--------------

[precision]

in VB

If ((Text1.Text Mod 2) = 0) Then
        MsgBox "Even"
    Else
        MsgBox "Odd"
    End If

.