Measuring voltage from a current transformer

[Archangel]

Hi Russ,
That looks like a good subject for your NV article. Hint hint . . . I would read it.

[docwisdom]

Ok,
It took me a while to grasp, but I think I got it now.
I had to bring up schematics to figure it out, but a resistor needs to be placed across the secondary leads of the CT. This was the magic thing that I didn't get at first.

Now your formula makes some sense.
Primary current max to sense - 20a
Transformer ratio 1000:1
5v/.02=250ohm

I only had a 275 to test with, but got some results with a voltmeter.
when running a 25w light bulb, it read .062v
100w light bulb read .224v

question is, from my voltage reading, how to I calculate back to the primary amperage?
---edit---
I think i figured this part out. A=(V*20)/5 or A=V*4
---end edit---
also, I will need rectifier to go from AC to DC. Do you have any schematics that would be appropriate for low voltage AC to DC?

[Darrel Taylor]

If the load will always be resistive, like light bulbs or heater elements then a "precision rectifier" and a simple linear equation will do the job.

If there are inductive loads, the resulting waveform will not be a sine wave, and you'll need to do an R-M-S conversion. Almost impossible with a PIC, unless that's the only thing the PIC is doing.

There are several RMS converter chips available that give a DC output so you can use a linear equation again. I like the LTC1966, but that's just because it's the only one I've figured out how to use. I'm not good with hardware.
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[docwisdom]

Loads will be anything that can be plugged into a 120v plug.
Most common will be lights, heaters, computers, other electronics, etc.

whats the difference between a precision rectifier and a full wave bridge rectifier? lemme guess, precision ..heh

last thing. I am good at getting things done once I have a detailed parts list. The circuit explains what what kind of resistors and op amps to use, but no specs on the diodes. Digikey carries ~10,000 varieties.

[Darrel Taylor]

Loads will be anything that can be plugged into a 120v plug.
Most common will be lights, heaters, computers, other electronics, etc.

Refrigerators, Sump Pumps, Compressors, Fans ...

They can all be plugged into a 120V outlet. And they would all be considered "Inductive Loads".
So you can forget about the Precision Rectifier.

Check out the datasheet for the LTC1966
At the bottom of the sheet in the "Typical Applications" | Single Supply RMS Current Measurement
Shows exactly what you need.

Added: Although you might want to increase the "Burden" resistor. 4mv/amp is hard to read with a PIC's A/D.
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[dhouston]

Toss the current transformer in the junk bin and get a hall-effect current sensor ffom Allegro Microsystems.

• http://www.allegromicro.com/en/Produ...rentsensor.asp

They have high isolation, handle AC or DC, come in a wide range of current capacities, output a DC voltage proportional to current, and are rather inexpensive.

[docwisdom]

i would, but as i mentioned in previous threads, i need for it to not interfere with the primary path. the hall effect devices require you to break the primary path and route it through the IC.

DT, just to satisfy my natural curiosity. what effect will you experience if you were to have an inductive load on the primary with a precision rectifier on the secondary?