How to isolate 10 bits from word variable?

[mat janssen]

A word consits of a high byte and a low byte. (see manual)
There is also a shift (right) possibility in PBP. (>>)
Only you have to copy the lsb of the high byte to the msb of the low byte after every shift.

[paul borgmeier]

Also try, as suggested by Mat

My16Bits = %1111111100000000
My10Bits=My16Bits >> 6 ; lose the lower 6 bits (same as divide by 64)

[rcbandwidth123]

Thank you for your response:

The problem I'm having is joining the entire Highbyte of the Word variable with the 2 MSB's of the Lowbyte to form my 10 Bits.

I know I need to concatenate the bits together,but I am getting a bit frustrated by this...If you or anyone else can show me the coding syntax for this operation I would appreciate it.

The concatenated bits will be placed in a word variable .

Down and out
Bob C.

[Acetronics2]

Pfouuuuuh !!!

A is a Byte - Lower Part of THE 16bits value VAL
B is a Byte - Higher Part ....

VAL.Lowbyte = A
VAL.Highbyte = B

That'a All ...

and VAL >> 6 is What you look for.

Final point.


Alain

[rcbandwidth123]

I now understand the process!!!....ACE-I honestly RTFM but I guess I just was not understanding.

In your honor Ace I have declared RTFM as a Word variable and will use it my program


Again,thanks for helping me out gentleman!!

Bob C

[mister_e]

some may have learn from this RTFM expression

http://www.rtfm.com/

Some also did come cofee cup