Advice on Input circuitry for 0-10v or Pot


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  1. #1
    malc-c's Avatar
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    So in essance its a straight divider, 5V (+ or - 0.25 ish of a volt).

    So how would you then take the 5v output and use this to give a voltage range the ADC can use to intern generate the PWM to dim the LED. I assum that any pot between 5v and gnd will thus be in parallel with the 9.1K, hence your comments regardig Ohms Law

    EDIT:
    Or have I missed something, in that the 0-10v stated in the original post is already a varible voltage between zero and 10v, rather than a fixed 10v supply ? If so then I can see your logic
    Last edited by malc-c; - 12th April 2008 at 10:12. Reason: Afterthought :)

  2. #2
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    i'm not sue if i follow you malc ... not sure you follow us too no pun intended

    You take the output and plug it directly to the PIC... straight, not much. Sugarless, fat-free, not much, zip, zero,nada. Want to use it to dim a LED? easy...

    ADCIN 0, ByteVar
    HPWM 1,ByteVar,Freq

    If i haven't missed anything in the OP request, he have an external source which provide voltage between 0-10V... and want to monitor it (for xyz reason) with a PIC, hence why the voltage divider.
    Steve

    It's not a bug, it's a random feature.
    There's no problem, only learning opportunities.

  3. #3
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    Quote Originally Posted by mister_e View Post

    If i haven't missed anything in the OP request, he have an external source which provide voltage between 0-10V...
    That's the part I missed - I was assuming it was a fixed 10v supply

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    I don't see why any PIC should be used here anyway
    Steve

    It's not a bug, it's a random feature.
    There's no problem, only learning opportunities.

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