So in essance its a straight divider, 5V (+ or - 0.25 ish of a volt).
So how would you then take the 5v output and use this to give a voltage range the ADC can use to intern generate the PWM to dim the LED. I assum that any pot between 5v and gnd will thus be in parallel with the 9.1K, hence your comments regardig Ohms Law
EDIT:
Or have I missed something, in that the 0-10v stated in the original post is already a varible voltage between zero and 10v, rather than a fixed 10v supply ? If so then I can see your logic
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