2.2v to 5v


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  1. #1
    Join Date
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    let's do some calc to see what happen...

    Ic(T1)=(12/10,000)=1.2mA

    Ib(T1)=(3/22,000)=0.136 mA

    a Hfe minimum will be Ic/Ib = 8.8 to make this work. it's usual and recommended to multiply the minimum Hfe by 5 or 10. so here between 45 and 90 will be the minimum.

    Looking at BC237 datasheet, Hfe min = 120, so it has to work.

    And yes i forgot to add some extra load at first calc. But you get the idea.
    Steve

    It's not a bug, it's a random feature.
    There's no problem, only learning opportunities.

  2. #2


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    Thanks Alain and Steve...appreciate the help, I will post back the update as soon I get to work with my project this weekend.


    Regards,
    Joe

  3. #3
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    If I may ask, why don't you use the ULN2001 that has no base resistor and a min Hfe of 1000? You can calculate the external resistor if necessary or connect directly to the low voltage output of the PIC you use.

    No additional transistors. Just a resistor, but I think is not necessary anyway.

    Ioannis

  4. #4


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    Hi everyone,
    Again thanks for the reply and the effort for helping me out. Thanks to Alain for his schematic because I got it to work. To be honest I found out later on that by removing the LED between the I/O and ULN2003A gave me the 5v needed for input to the 2003A which solved my problem... anyways I guess I'm learning new things...


    Thanks all,
    Joe

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