Make me some code..

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  1. - 12th September 2007, 11:21 #1
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    just simply illuminate the LED as wired in that schematic...
    Oh. BobK is right.
    LED will never illuminate according to circuit.
    Thought-habits can harden into character. So watch your thoughts.

    (__)
  2. - 12th September 2007, 11:27 #2
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    Talking Turn your tongue in your mouth 7 times before ....

    Hi, Everyone ...

    I Win !!!

    Just Reverse supply voltage and the Led will light ...

    Yesssss ... the Port Inputs clamp diodes Help !!!

    Thank you very much, Mel ... I'm waiting for my Bucks !!!

    Nobody told the Pic might stay Alive !!!

    Alain
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    Why insist on using 32 Bits when you're not even able to deal with the first 8 ones ??? ehhhhhh ...
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    IF there is the word "Problem" in your question ...
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  3. - 12th September 2007, 13:46 #3
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    xobx,

    The demand "Make me some code" as you have seen will not get you anywhere.

    If you really want to learn, study, write some code and then ASK for help.

    Here is someplace to start http://www.picbasic.co.uk/forum/show...ghlight=timers

    All I had to do was search the forum for "timers".
    Dave
    Always wear safety glasses while programming.
  4. - 12th September 2007, 13:46 #4
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    Good try Alain, but the 1N4004 across the input shorts-out the supply...

    Game is still open... (excludes supplying the +5v reverse-way round from a high-current source which smokes-out the 1N4004 first, and then the input capacitor, then destroys the PIC and finally lights the LED (which has a panel legend above it saying "now you're completely screwed!").
  5. - 12th September 2007, 14:13 #5
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    Melanie is CORRECT

    the circuit is designed wrongly. Forget the micro. Even by connecting the ground at anode of LED it would not light. the LED woud have been wired otherway round. this configuration is like a protection diode across a relay coil driven by a transistor. Perhaps XOBX has to improve on his / her funda of harware design.

    YES, it will light, if by using the port pin RB0, we switch a higher voltage than +6.4V to the anode of LED.
    Last edited by mvs_sarma; - 12th September 2007 at 14:15.
    Regards,
    Sarma
  6. - 12th September 2007, 14:33 #6
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    Reminds me of an Industrial Electronics exam I sat for back in the eighties. The circuit was a pretty basic push-pull amp in which we had to write an essay what happens once power was applied.
    The schematic had the diodes on the bridge rectifier for the power supply connected wrong.
    I just wrote that 2 diodes across the 15VAC supply would blow up. I was the only one that got it right.

    Wilson
  7. - 12th September 2007, 16:03 #7
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    Quote Originally Posted by Wilson View Post
    The schematic had the diodes on the bridge rectifier for the power supply connected wrong.
    Sounds like my first attempt at building a bridge rectifier when I was about 11 years old.

    What I actually constructed was a "ring rectifier" with all the diodes pointing in a circle. There was an almighty bang when I turned the power on and my diodes were no more. Didnt make that mistake again
    Keith

    www.diyha.co.uk
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  8. - 12th September 2007, 14:20 #8
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    Hi, Mel

    You've wrote it ...

    It had to make some smoke, BUT IT WORKS !!!

    Do you have some Scottish elders, to modify the rules AFTER the beginning of the Game ??? ...

    Bad looser, I Wonder, hmmmm ???

    LOL

    Alain

    PS: Note, I often saw ( some years ago ) LEDs drawn in a circle ... but drawn "reverse" connected.
    This could simplify the game ...
    ************************************************** ***********************
    Why insist on using 32 Bits when you're not even able to deal with the first 8 ones ??? ehhhhhh ...
    ************************************************** ***********************
    IF there is the word "Problem" in your question ...
    certainly the answer is " RTFM " or " RTFDataSheet " !!!
    *****************************************
  9. - 12th September 2007, 14:37 #9
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    lol - Short of reinventing the diode, that's impossible.
  10. - 12th September 2007, 19:37 #10
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    Quote Originally Posted by Melanie View Post
    Game is still open...
    How about: 'accidentally' cut the wire directly above the "16F628" in the circuit diagram, then PORTA.4=0, then PORTB.0=1, and press the button. LED=lit!
  11. - 12th September 2007, 20:26 #11
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    I think you just made $20.
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