Sure it works.
But PBP uses integer math. So there are no decimals.
With STEP -2 the loop will execute 3 times, with the values 5, 3, 1 in DigLoop.
Since it's Integer math, (6-DigLoop)/2 will return 0, 1 and 2 respectively.
hth,Code:loop Buf((6-DigLoop)/2) = ((Value DIG DigLoop) << 4) + Value DIG (DigLoop -1) 5 BUF( 0 ) = ( $00 ) + 0 = $00 3 BUF( 1 ) = ( $10 ) + 3 = $13 1 BUF( 2 ) = ( $80 ) + 9 = $89





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