At the risk of starting another argument/discussion...
I don't know if I'd go straight to ground without a series resistor limiting the current to at least the pins current carrying capability, 25mA give or take. I'd throw at least a 200ohm resistor inline with it. I know the pin is set up as an input...but what happens if the program gets changed and the pin gets set up as an output with a logic high on it?
Assuming the program stays the way it should, then, yes, straight to ground on an input pin...I'm just thinking a bit out in left field...
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