Bit set question

[Darrel Taylor]

Yes. The (channel + 1) bit.

By putting the .0 after the variable name, it forces PBP to use it as a BIT Array, regardless of what the original variable was defined as.

If you use .0 then it starts at bit0
If you use .5 it starts at bit5. An index value of 0 will set bit5. An index of 4 will set bit0 in the next byte.
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[nverma]

Thanks a lot!