
Originally Posted by
skimask
Right...I understand that. I'm still trying to make you understand.
Again, I ask you to do a search in the PBP manual for floating point math and tell me what you come up with (same hint: we've already been through this in January, see post #8 of the "16f877 with LM335 problem" thread ).
I have read the manual for floating point very well and i have see post #8 of the "16f877 with LM335 problem" thread.
i use this:
Code:
' forwardpower = 400
' reflectedpower = 20
B0 = forwardpower/reflectedpower ' = 400/20 = 20
B1 = 10000/B0 ' = 10000*1/20 = 500
B2 = SQR B1 ' = 22,360679
B3 = (10000+B2*100)/(100-B2) ' = (10000+22*100)/(100-22) = 12200/78 = 156,4
Lcdout $fe,$90, "SWR : ",DEC (B3 DIG 2),".", DEC (B3 DIG 1),DEC (B3 DIG 0)
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