Need advice for 74VDC power supply


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  1. #1
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    Default Need advice for 74VDC power supply

    Hi everyone,

    I have researched google, digikey and E-bay and I have some ideas but I wanted to come here before I made my final decision. I have a low power application where the input voltage can be anywhere from 50VDC to 90VDC (extreme cases) but the nominal would be about 74VDC. There is an off the shelf power supply that will supply 1.25A and the output is 12VDC but it's $50 and too big for my application. I thought about using two power resistors as a voltage divider and the supplying a 7805 to run the PIC. I have seen other DC-DC converters on the internet and they are really expensive. I would only need to run about .5A max for everything on my circuit. If I need to, I can drop the current to .1A. Are there any other ideas that I can use to accomplish this?

  2. #2
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    Smile TL783 from Texas Instruments

    TL783 from Texas Instruments

    3-Terminal 700-mA High-Voltage Adjustable Positive Voltage Regulator

    Output Adjustable From 1.25 V to 125 V
    When Used With an External Resistor Divider

    700-mA Output Current

    Full Short-Circuit, Safe-Operating-Area, and Thermal-Shutdown Protection

    0.001%/V Typical Input Voltage Regulation

    Read the Data Sheet!
    http://focus.ti.com/lit/ds/symlink/tl783.pdf

    Less than $2 USD
    HTH
    -Adam-
    Ohm it's not just a good idea... it's the LAW !

  3. #3
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    Default

    yes, and make sure you have some heat-sink around. Some switching regulator could help. have a look to LM5010
    Steve

    It's not a bug, it's a random feature.
    There's no problem, only learning opportunities.

  4. #4
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    Default Linear or Switching

    Quote Originally Posted by mister_e View Post
    yes, and make sure you have some heat-sink around. Some switching regulator could help. have a look to LM5010
    I agree.
    The voltages involved can quickly rack-up Watts.
    He should keep in mind the heat generated is from the voltage drop within the device, and the amperage through it. With 90 Volts input and 12 Volts output you have considerable voltage differential. The data sheet claims assume you have dealt with the heat, and removed it.

    Second pitfall:
    Use an input (bypass) capacitor.

    Third pitfall:
    Mind the "Minimum output current to maintain regulation".

    As you said the switching regulator could help. More efficient and a lot less heat to dump. Little more engineering though.

    -Adam-
    Ohm it's not just a good idea... it's the LAW !

  5. #5
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    Default

    Thanks for the replies everyone. I have looked at the datasheet and have some further questions for electronic wizards.

    1. The minimum current is not a problem. I will just put an LED to indicate power and that should take care of that problem.

    2. The data sheet says, "An input bypass capacitor is necessary
    only when the regulator is situated far from the input filter." I will put one anyway just incase but would a .1uF cap be sufficient?

    3. The data sheet also says, "An output capacitor, although not required, improves transient response and protection from instantaneous output short circuits. Excellent ripple rejection can be achieved without a bypass capacitor at the adjustment terminal." Again, would a .1uF cap be sufficient?

    4. I don't understand the capacitance issue. The data sheet says, "The TL783 regulator is stable without bypass capacitors; however, any regulator becomes unstable with certain values of output capacitance if an input capacitor is not used." In another section the data sheet says, "when an instantaneous short circuit is applied to the output, both ringing and excessive fall times can result. A tantalum or aluminum electrolytic bypass capacitor is recommended to eliminate this problem." Is the electrolytic acting like a small battery? How can I measure the output capacitance? Is there a cap that will work for every value?

    Thanks for the help, this chip seems to be exactly what I need.

    Chris

  6. #6
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    usually 10uF tantalum + 0.1uF ceramic at the input and at the output cover almost everything.
    Steve

    It's not a bug, it's a random feature.
    There's no problem, only learning opportunities.

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