How do I convert an internal variable into frequency

[Ioannis]

Hi! You have not mentioned if the values come with a regular rate. If they do then I suppose you have to use maths (diferrentiation) to get your value.

I am not an math's expert though.

Another method might be to use Interrupts and check the value from A/D. Then use select case commands to decide whta to do.

Ioannis

[schlaray]

For sake of argument, let us say that I am using a temperature sensor. Normally the temperature (output of the A/D) is constant. When the temperature changes, I want to know the rate of change.

[HenrikOlsson]

Hi,
You need to sample your analog signal at precise intervals. Then, to find the rate of change, it's just a matter of comparing the last reading with the new one.

At what interval you sample depends on the expected rate of change of the signal. If it's temperature you should perhaps sample once every second, minute or even hour but if it's voltage perhaps once every mS or even faster - it all depends on the application.


/Henrik Olsson.

[Ioannis]

Henrik, Hi!

Just comparing the samples, would require a lot of if then or select case commands. That is why I suggested differentiation. Also now it came to my mind that differentiation could happily be done in hardware with op-amp's. Select the proper R-C values according to the signal and then get an analog value, proportional to the rate of signal change.

I would prefer the digital way though...

Ioannis

[HenrikOlsson]

Hi Ioannis,
OK, you lost me there.... I'm no math expert either but isn't differentiation the same as derivative ie. the difference between two samples with respect to time. (in this case)

Let's say we read a voltage once every second first reading is 2.2V second reading is 2.5V the rate of change is then 0.3V/second third reading is 4.0V, rate of change is now 1.5V/second and so on.

It may very well be that I misunderstood the original question, if so you'll have to excuse me, but he said he was looking for the rate of change.

/Henrik Olsson.

[Ioannis]

Well the derivative is a number (no units associated with). So the derivative of a function that represents volts (say the 220*sin(t)) is not volts. Is a simple number (negative or positive) that represents the direction of the change or the will of the function to do a change. The larger positive number the more steep the change is.

Hope it made it a little more clear if I understood it...!

Ioannis

[HenrikOlsson]

Ioannis,
Really, I think we are basicly saying the same thing here, however.... You wrote:

Well the derivative is a number (no units associated with).

I think this is where you are wrong. The derivative is the rate of change. But you cant just say that the rate of change is 7. You have to say 7 this per that otherwise it doensn't make sense IMO. For example 1.5V per second or 25degrees per hour or 15m/s per second etc.

I found this on Wikipedia:

In mathematics, a derivative is the rate of change of a quantity. A derivative is an instantaneous rate of change: it is calculated at a specific instant rather than as an average over time. The process of finding a derivative is called differentiation. The reverse process is integration. The two processes are the central concepts of calculus and the relationship between them is the fundamental theorem of calculus.

Again, I believe we're meaning the same thing but without assigning units to the numbers they just doesn't make sense.

/Henrik Olsson.