Serin serout problem

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Ok leramuer,
Since I am too lazy to read 288 pages of this post over, I am not going to ASSUME anything. So here goes; Current flow, not to be mistaken with electron flow, current flows from positive to negative. The arrows in LEDs and Transistors indicate the current flow direction. Maybe you know all this, like I said, I will assume nothing. (1) Anyway, if you have a pic which outputs logic High, then you hook that port to pin 1 or pin 4 of the opto coupler, and pins 2,3 would hook to ground.(2) If ypur PIC outputs logic low then you would hook the port to pin 2 or 3, pins 1 and 4 would hook to the positive supply. now if your relay has one leg hooked to positive then the other leg would hook to pin 6, or 7.
If your relay has one leg hooked to ground, then the other end should hook to pin 5 or eight. As I said current flows in the direction the arrows point. It is that simple. CAUTION: Be sure to use current limiting resistors on the emitter side of the opto couplers as they only operate at 1.5v max 20ma so as not to fry them.