problem with output RA2 and RA3

[savnik]

When I read the datasheet of the 16F88 then I see other configurations than you filled in at adcon0 and adcon1.
You say:
ADCON0 = %11100001 ' Configure and turn on A/D Module
I read for this:
do nothing with adcon0
You say:
ADCON1 = %00000010 ' Set PORTA analog and RIGHT justify result
I read for this:
adcon1 = %10000000 'only right justify and nothing about set port a.

I read this
ADCON0.0=1 ' A/D converter module is operating

[mat janssen]

The adcon0,0 is an internal bit to tell us what the condition is of the adc.
You need it if your programm is made in assembler.
All of this is solved for you in the picbasicpro compiler.

[savnik]

i change with this:

    CMCON = 7                       ' PortA = digital I/O    
	ANSEL = %00000011               ' Will set RA0-RA1 as analog and all others as digital 
    TRISA = %00000011  
    ADCON0 = %11000001	            ' Configure and turn on A/D Module
    ADCON1 = %00000000 	            ' Left justified. Six Least Significant bits of ADRESL are read as ‘0’

and work but i want only the positive result and not the negative of command: if (value - P2) >= 1
23 - 25 = -2 (P2=25)
27 - 25 = 2 (P2=25)
the pin PORTA.2 turn on , and for -2 and for 2 , but i want only for 2.
How to make this;

[mat janssen]

Test if the first number is greater then the second number and then do the subtraction. If otherwise then do nothing.

[savnik]

Test if the first number is greater then the second number and then do the subtraction. If otherwise then do nothing.

Thank you.
I use this code:

    If value >= P2 then
        If (value - P2) >= 1 then
            PORTB.1=1
            else
            PORTB.1=0
            endif
        endif