Interrupt Or I Am Going To Die

[sayzer]

Couple of things to remember.

1. It is not a good idea to post an e-mail on the forum. You will get thousands of junks to your e-mail. I suggest that you remove it right away and PM to members instead.

2. You are not using PBP, but this is a PBP forum

3. Lets keep this issue on this forum, so that it can be some help to some other members having similar issue.


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Let me try to start by changing the code to PBP first.

In your schematic, I would use Interrupt on RB0 pin, instead of RB6 pin. May be you should change that first.

Then, assuming you are now using RB0/Int, we set Intcon Bit 4: RB0/INT External Interrupt Enable bit. Thus, we end up with INTCON = %10010000

Now the code should look like below but remember it is with PBP statements. You can get around it.

TRISA =  %00000000     'All output.
TRISB =  %00000001     'RB0 is input, rest is output.
INTCON = %10010000     'Enable global (Bit7) interrupt, enable RB0/Int (Bit4) 
ON INTERRUPT GOTO FLASH

                                                 
loop:
    PORTA = 255
    PAUSE 200
    PORTA = 0
    PAUSE 200
    GOTO loop

disable

    FLASH:
        PORTA = 0
        INTCON.0 = 0

RESUME
ENABLE

END

Also, why do you have to use interrupt?


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[SteveB]

Add this line before your main loop:

RBIF var INTCON.0

Add these two lines to your flash subroutine:

@ MOVE?BA PORTB 'Read PORTB by placing it WREG
RBIF = 0 'Clear the interrupt flag

Also, read the pic datasheet on interrupts and under the I/O Ports section. You should find were it mentions both of items added to the ISR.

Steve

[kunguz]

@ MOVE?BA PORTB

IDE did not recognize this line

[kunguz]

RETLW PORTB.6 when I use this line in top flash block, it doesn't do anything and continue to it's job

[SteveB]

I shouldn't have been so brief in my first response, so here is a little more explaination. But, you would be well served to learn more about interrupts if this explaination is still confusing.

@ MOVE?BA PORTB

This is a PBP internal macro which reads PORTB and moves the value to W register. It results in the asm instruction: MOVF PORTB, W This is the simplist way to read PORTB to end the mismatch which triggers the interrupt on change. No variables and only one line of code are required.

RBIF var INTCON.0

This statement assigns the Interrupt Flag (at INTCON.0) used for the PORTB's interrupt on change to the name "RBIF" (which is what it is refered to in the PIC datasheets).

RBIF = 0 'Clear the interrupt flag

This statement clears the interrupt flag, which is also required before exiting the interrupt service routine (ISR), or the program will continue returning back to the ISR. No matter what type of interrupt you use, the Interrupt Flag for that particular interrupt must always be cleared before exiting the ISR, or you will end up in an endless loop.

Steve

[SteveB]

As Sayzer asked,

Also, why do you have to use interrupt?

Using interrupts may just be overcomplicating the application. Could you just pool the I/O line in question in your main loop?

Steve

[sayzer]

As Steve repeated,

May be, a code like the one below could do the job for you, may be.

TRISA =  %00000000     'All output.
TRISB =  %01000000     'RB6 is input, rest is output.

IN_PIN VAR PORTB.6

                                                 
Loop:

    WHILE IN_PIN
        PORTA = 255
        PAUSE 200
        PORTA = 0
        PAUSE 200
    WEND
    PORTA = 0

    GOTO Loop

END

Not a real drop-in interrupt compatible code but may work in some cases.

Try...

[kunguz]

Thanks alot for your helps and replies;

It finally works with this code below , but to return to main progress takes approximetly 1:20 minute. I think there might be problem with my schematic; If ISIS is that good, may be simulation thinks about small arcs that is created by button .Which gives a unexpected voltage levels for a short time to the PORTB.6.So PIC interrupts it's self for more then one time.The reason that took so long, might be that. Is this the problem or is it still in software _?

device 16f84a
ON_INTERRUPT goto flash
intcon = %10001000
input portb.6

loop:
high porta
delayms 200
low porta
delayms 200
goto loop

disable

flash:
delayms 1000
MOVF PORTB, W
low porta
intcon.0 = 0
CONTEXT RESTORE

end

[kunguz]

After removing delayms1000 waiting for interrupt takes much shorter time like 1 sec. And I look with an osiloscope in simultion to the portb.6 which i see is a clear 5V. http://ww1.microchip.com/downloads/e...tes/00566b.pdf after reading this I get the feeling like this circuit did not fit for a small pulse width. Is this the problem or am I doing something wrong in programming

[kunguz]

After using this new code below, I get value of sayi +2 each time I click.

device 16f84a
ON_INTERRUPT goto flash
intcon = %10001000
input portb.6 ' Bu pinleri sıfırladıktan sonra alıcı olarak ayarlamalısın
dim sayi as byte
sayi = 0

loop:
high porta
delayms 200
serout portb.3,16780,[Dec sayi ,13]
goto loop

disable

flash:
MOVF PORTB, W
low porta
intcon.0 = 0
sayi = sayi + 1
CONTEXT RESTORE

end

[sayzer]

Hi Kunguz,

In your code, which you said works, how did you get "HIGH PORTA" or "LOW PORTA" work?


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