ADC Channels

[ErnieM]

ADRESHI has the most signifigant bits, leaving ADRESLO with the least signifigant bits.

The data from the A2D is 10 bits wide... so the question is where to put 10 bits into 2 seperate 8 bit result registers.

If you left justify, you space everthing so the highest (most sig) data bit align with the highest (most sig) register bit.

Right justify puts the lowest data bit in line with the register's lowest bit. That means the hi register only has the top 2 sig bits.

When you left justify, as the hi register has the most sig 8 bits it also has the 8-bit (non rounded) result.

Hope this is more helpful then confusing.

[amindzo]

Hi,
you don't need to use 10 bit A/D. you can use 8 bit , that is easier than 10 bit.
like this:

define OSC 4
TRISA = %11111111
x var byte
ADCON1 = %00000010
adcin 0,x ' 0is the channel number and x is the variable
end

you don't need to connect the Vref+ and Vref- to somewher.

if you want to use 10 bit ask me again yo tell you.