Delta-Sigma-ADC in Assembler embedded in PBP, increasing resolution

[Ingvar]

Result_h is the high byte(8bits) of the wordsized(16bits) result. Result_l holds the lower 8 bits.

[selbstdual]

I don't understand this. How do you combine these two to get a Dez-number between 0 and 1023 ?

[Ingvar]

Ok, time for somebody else to step in. I don't have the patience, time and/or languageskills to explain how hex, binary and decimal correlates. I recommend that you buy a book that expalins the basics of "microcontrolling". Can't give you any advice on good books since i haven't needed one for 20 years.

Good luck
/Ingvar

[HenrikOlsson]

Hi,
Haven't followed this from the beginning but I'll jump in here real quick.

A word is 16bits. A byte is 8bits. A word consists of 2bytes a high and a low. To combine 2 bytes into a word you can do:

MyWordResult var WORD

MyWordResult = Result_h * 256 + Result_l
HSEROUT [#MyWordResult,10]

If Result_h is 100 in decimal and Result_l is 25 in decimal. Your result would be 25625 in decimal. Or if you like in binary.

         H I G H     L  O  W
         B Y T E     B Y T E
MSB---> 01100100  00011001 <----LSB

See? The high byte is 100 and the low byte is 25.

Since the most significant bit in the low byte equals to 128 the least significant bit in the high byte equals to 256. That is why you multiply the highbyte by 256.

Or seeing it as 16bit word:

LSB MSB
1+0+0+8+16+0+0+0+0+0+1024+0+0+8192+16384+0 = 25625

/Henrik Olsson.

[selbstdual]

MyWordResult = Result_h * 256 + Result_l

This is what I was looking for. Plain and simple. Thank you.