Automotive Use

[Acetronics2]

Hi, Joe

A simple opto-coupler ( 4 pins footprint for the TLP 620 i.e. ) ... will do it really nice.

And avoid ground interconnections too !!!

Alain

[Archangel]

muddy0409
Your idea to use LM7805 integrated circuit regulators is a GEM, it works well and it takes up way less room on the circuit board than an opto coupler, opto isolator and requires no resistor for the led as in the opto device, thereby making PC board layout a snap. Very innovative, Thanks Again! JS

[BigWumpus]

OK,

I use a 100k-resistor in series and it works (yes, a PIC has clamping-diodes).

Am i bad or evil ?

[DynamoBen]

OK,

I use a 100k-resistor in series and it works (yes, a PIC has clamping-diodes).

Am i bad or evil ?

Is this the "proper" way of sensing the state of a 12V source?

I have also seen voltage dividers or transistors used. Whats the best method for a 12V sense? (just detecting on (0V) or off (12V))

[Archangel]

Is this the "proper" way of sensing the state of a 12V source?

I have also seen voltage dividers or transistors used. Whats the best method for a 12V sense? (just detecting on (0V) or off (12V))

I decided to use the suggestion below, I would never use just 1 resistor, 2 would make a voltage divider, I wanted 5 volts across the useful voltage range an automotive system spans, and that's what the suggestion below provides, you do not have to go the expense of 1 amp regulators either, just the little TO-92 cased ones work fine.
JS

One thing I have seen used, but not used myself, is to use 78L05 regulators with the input to the high voltage you want to detect, and the 5v output going to the PIC input pin.
Seems pretty good in theory, as any variations in the input will just be absorbed by the regulator. A bit better than voltage divider etc???

[jessey]

Hello,

I had an application where I had a motion detector that outputted a 12vdc signal to a 16f84a and I passed the 12vdc signal through a 22k resistor to the pic input pin. I also tied a 10k resistor from the pic pin to -5 v (ground) along with a 10uf capacitor to -5 v (ground) the two resistors formed a voltage divider. That was years ago and it still works great.

Here is a great Potential Divider Calculator that's real easy to use and according to the calculator my voltage to the pic input pin would be 3.75vdc.
http://www.electronics2000.co.uk/calc/calcdiv.htm

It was on another list years ago that, that was recommended and like I said, its still working good.

Good Luck
jessey

[DynamoBen]

The voltage regulator would be overkill for me. I'm just sensing the state of a 12V source. It’s an automotive application so it could be anywhere form 12-14V. So I guess the best bet is a voltage divider. I would assume any odd spikes in voltage would be taken care of by the internal clamping diodes.

[BigWumpus]

Is this the "proper" way of sensing the state of a 12V source?

I have also seen voltage dividers or transistors used. Whats the best method for a 12V sense? (just detecting on (0V) or off (12V))

The last 3000-4000 parts we have sold have a relais to switch the power after switching the ignition. Before, there are sometimes little voltage on the pin.

In our current design, I use a zener-diode (5,1V) followed by a 4k7-resistor towards griund and a 100k-resistor to the port.

My intention was to reject all this little voltages on the ignition-power-line comind from other devices...