After reading another thread I found a solution. While the variable B0 contains the string simply sending B0 out via debug isnt showing the string, to do this I changed it to debug b0[0],b0[1]
I assume, correct me if I am wrong that if I only send debug b0 then it assumes debug b0[0]

if any one is interested, the thread that I found this on is
http://www.picbasic.co.uk/forum/show...hlight=strings