A to D on the PIC16F687

[jblackann]

This somewhat works but I need to work through a way that it will display the value, 2.004 instead of 2.4 because the way I did it is with W0 = 5*AD_Value (AD_Value could be 0 to 1023). Then I did:
AD_VALUE_HIGH = W0 / 1023
AD_VALUE_LOW = W0 / 1023

THEN LCDOUT, $FE, $C0, #AD_VALUE_HIGH, ".",#AD_VALUE_LOW, "VDC"

I am not sure what you meant by using the DIV32 command. Can you please explain more? Thanks.

Josh

[psdayama]

Hey ! all the time I thought I was most dumbo person for Basic espeacilly for
pretty type.
Now Im relieved that there is atleast one more and may be many thousands!
I hope Josh takes some troubles with searching on forum.
I don't have experience with PIC or other Basic but in assembly there is
DIV32 routine - sort of macro - for dividing 32bit version.
wish U best!

[Acetronics2]

I am not sure what you meant by using the DIV32 command. Can you please explain more? Thanks.

Josh

That's a simple function of PbP :

PBp does internally the 16x16 multiplication ...

then the result is internally stored into 2 separate WORDS ...but you can't ( normally !!! ) access them nor make another thing without tearing them !!!

A function was implemented, DIV32, that can divide those 2x16 bits by another 16 bits max value

so, first, you do the mult.:
WWRes = W1*W2
and the very next line MUST be
Wres = DIV32 W3

This realizes the Word1*Word2/Word3 operation, despite PbP do not work with more than 16 bits !!!

Just need to use for WWRes an already declared WORD.

For details see $ 4.17.8 page 35 ...

Alain