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  1. - 5th July 2006, 13:40 #14
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    jblackann
    jblackann is offline Junior Member
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    This somewhat works but I need to work through a way that it will display the value, 2.004 instead of 2.4 because the way I did it is with W0 = 5*AD_Value (AD_Value could be 0 to 1023). Then I did:
    AD_VALUE_HIGH = W0 / 1023
    AD_VALUE_LOW = W0 / 1023

    THEN LCDOUT, $FE, $C0, #AD_VALUE_HIGH, ".",#AD_VALUE_LOW, "VDC"

    I am not sure what you meant by using the DIV32 command. Can you please explain more? Thanks.

    Josh
    Last edited by jblackann; - 5th July 2006 at 14:48.
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