There has to be an easier way!

[Christopher4187]

I don't have much experience with the lookup command and I don't understand what the manual states. I will post the code here and someone let me know if I can clean it up please.

B1=8
B2=6
B3=11
B4=15

'I NEED TO TAKE THESE INTO BINARY, BUT I CAN'T FIGURE OUT HOW TO DO IT. WITHIN B1, I NEED R1, R2, R3 AND R4 TO EQUAL THE BINARY OF B1, LIKE THIS

'THE OUTPUT OF B1 LOOKS LIKE THIS:
R1=0
R2=0
R3=0
R4=0

'THE OUTPUT OF B2 LOOKS LIKE THIS:
R5=0
R6=1
R7=1
R8=0

'AND SO ON BUT THE PROBLEM IS THAT I HAVE TO SCAN 16 DIFFERENT SIGNALS AND IF THERE WAS A WAY TO SAY SOMETHING LIKE

B1,B2,B3,B4=R1 THAT WOULD BE GREAT. SO, R1 EQUALS 8 AND B1=0, B2=0, B3=0 AND B4=1. IS THIS POSSIBLE?




'I HAVE TO WRITE MY CODE LIKE THIS

IF B1=1 THEN

[Christopher4187]

I re-read what I wrote and it may be a bit confusing. Here is the short story:

b=7 now I need to extrapolate to binary


r1=1
r2=1
r3=1
r4=0


If it's still not clear, let me know.

[mister_e]

maybe i don't understand what you need but lets assume
B1= 11110000 bin => F0 hex => 240 decimal
B2=00001111 bin => 0F hex => 15 decimal

even if you define
B1=$F0
OR
B1=%11110000
OR
B1=240

It do the same thing.

IF B1=$F0 then....
IF b1=%11110000 then ....
IF B1=240 then .....

Maybe i need to sleep, or it's really what you need

[mister_e]

HONK! i think i got it.

Let's say B1=%11110000

R0 should be Bit 0 of B1, R7 should be Bit7 of B1... i'm i right?
If so...
R0=B1.0
R1=B1.1
R2=B1.2
R3=B1.3
..
...
R7=B1.7

[Christopher4187]

Steve,

You solved another one of my problems! Yes, to answer your question, I want to have a decimal number and convert that to binary. In that binary number, take each bit and it represents another number. So, within one number I extract 8 different boolean numbers. I'll try your suggestion but I do think it will work.

Thanks,

Chris

[Christopher4187]

I see one small issue.


For example, I know that b1=9 which is 00001011.

If b1=9 (the decimal number), how can I let PBP know that it is actually 00001011 (the binary number).

Or, can I simply go

R0=B1.0
R1=B1.1
R2=B1.2
R3=B1.3