Transformerless Power Supply


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  1. #1
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    Thumbs down X'ferless power supply

    OK, "nothing is impossible!!!" is Adidas ad.
    But have U considered the power dissipation in regulator?
    Capacitor voltage divider is 'lossless' so there is hardly any dissipation
    in dropper.
    Anyway we expect Volkov to announce his result.Although his use
    of Bipolar instead of MKT is little deviation I think his ckt will work OK.
    Best Luck to all who want to use same method. I have constructed
    10s of units with such supply and are working OK last 2-3years.

  2. #2
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    Default

    Hi,

    With a current of 25mA the power dissipation will be less than 1 watt.

    30V AC - 1.2V (rectifier loss) = 28.8V
    28.8V x 1.41 = 40.608V DC
    40.608V - 5V = 35.608V
    35.608V x 0.025A = 0.8902 W

    * * *

    Not in this project but maybe one day you will need a voltage
    regulator with an input voltage up to 60V.

    http://www.national.com/pf/LM/LM317HV.html

    Best regards,

    Luciano

  3. #3
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    Default Its getting HOT!

    Well estimated 1watt loss can heat LM317HV quite a bit.
    I think that in the price of that regulator U can buy 2MKT capacitors
    easily (Atleast in this part of world )
    Please make calculations as follows:
    30V ac = 30 x 1.41 = 42.42 volts DC
    - 1.2volts drop = 41.22 volts - 5volts output = 36.22V
    x .025A = 0.9055 Watts.

    One needs big heatsink for this.

    The purpose of circuit is to get lower voltage without transformer
    and not much regulated voltage is required.

    When required I will certainly use HV regulator if called for.
    otherwise I will use switching one to make it "cool" !

    Thanks a lot for suggestion.

  4. #4
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    Quote Originally Posted by psdayama

    One needs big heatsink for this.
    Your statement is not accurate.

    1 Watt of power dissipation without heat sink is possible with a LM317HV/TO220.
    Below you can see how to calculate the maximum allowable power dissipation without heat sink.

    Best regards,

    Luciano

    Code:
    How to calculate the maximum allowable power 
    dissipation without heat sink:
    
    
    PD MAX = TjMAX − TaMAX
             _____________
                 Rja
    
    PD MAX = Maximum Power Dissipation (Watt)
    
    
    TjMAX = maximum junction temperature (°C) 
    For the LM317HV the operating junction temperature range is 0°C to +125°C.
    
    
    TaMAX = maximum ambient air temperature (°C) 
    Room temperature or temperature inside enclosure.
    
    
    Rja= thermal resistance from junction to ambient without heat sink (°C/W) 
    For the LM317HV/TO220 is 50 °C/W.
    
    
    Example ambient air temperature 45°C: 
    
    125°C − 45°C
    __________    =  1.6 Watt 
       50°C/W
    
    
    With an ambient temperature of 45°C, the maximum power dissipation 
    of the LM317HV / TO-220 without heat sink is 1.6 Watt.
    
    With an ambient temperature of 75°C, the maximum power dissipation 
    of the LM317HV / TO-220 without heat sink is 1 Watt.

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