Math Formula / Variable Problem! Help!

[Charles Linquis]

Yes it would. Sorry, my error.

So, the best you could do is to multiply by 50 and divide by 643.
You could possibly get closer by using a different multiply/divide ratio.

Another option would be to use the DIV32 function.

[Melanie]

> Lets say I get a reading on the ADC of 11260.

Well, that in itself would be a problem... your 10-bit ADC shouldn't give you readings outside the range 0-1024.

Do the *5000 multiplication first, this in effect would cause an overflow from a word variable, but if immediately followed by a DIV32 (as Charles suggested) would result in an integer value.

So your input of 0-1024 multiplied by 5000 and divided by 64320 would result in a range of 0-79 which is very small and you lose a great deal of precision.

You can add TWO additional signigicant figures by multiplying by 50000 and dividing by 6432, this will then give you a range of 0-7960 which then by using the DIG function will allow you to extract the digits and insert a decimal point displaying your two decimal points to give you 0-79.60

Always work within a WORD variable but if you must spill out of it momentarily, immediately use the DIV32 function to come back.