Arithmetics ???
Hi, Houa
The first step is to use the brain ...
by multiplying a per 1000 and B per 100 ... you get integers, and so on.
AA = 34 030 * 1E-5
BB = 7 230 792 * 1E-3 ... over 16 bits, so,The second step is to define the precision of the result you want ...
X = - 7 305.5717 ok ... but what is the real meaning of the last digits ???
Here you find THE GOOD QUESTION ....
10 Bits for an ADC or DAC is .1 % ...
12 Bits ......................... is .025%
do you know lots of Pic level peripherals with a better accuracy ??? Do you know how to realise those circuits ???
so, 1 of 12 bits of your result is 1.8, say 2 ...
.5717 really do not mean anything here, in the real world !!!
Now, If you really want to do maths for maths ...
Have a look to Melabs site, you'll find two valuable solutions
1) Microchip FP files to " include" to your program
2) arithmetic co-processor ... wich is the most simple Way.
The last solution is to change compiler ( no, no ... not on the head ) or processor ... where those solutions are already cooked implemented.
Hope it helps you to better see the truth !!!
Alain
************************************************** ***********************
Why insist on using 32 Bits when you're not even able to deal with the first 8 ones ??? ehhhhhh ...
************************************************** ***********************
IF there is the word "Problem" in your question ...
certainly the answer is " RTFM " or " RTFDataSheet " !!!
*****************************************
Bookmarks