Display 2 WORDs as a 32bit integer

[HenrikOlsson]

Richard,
Just wanted to thank you once again, the code is now incorporated in my project and I can display my two 32bit variables nicely.
I hardcoded the divisor to 100k and got rid of the Divisor variable. It grew the codebase by 230bytes and 34bytes of RAM out of which 11 is an array to which I write the result

DWORDtoString:
    CALL DivBy100k

    ' QUOTL top word, Remainder low word.
    ' Get Remainder into PBP system variables in preparation for DIV32
    ASM
        MOVE?BB   Remainder, R2
        MOVE?BB   Remainder + 1 , R2 + 1
        MOVE?BB   Remainder + 2, R0
        MOVE?CB   0, R0 + 1
        RST?RP
    ENDASM

    Result = DIV32 10000
    Remains = R2
    
    IF QUOTL THEN
        ARRAYWRITE DWordString, [DEC QUOTL, DEC Result, DEC4 Remains, 0]
    ELSEIF Result THEN
        ARRAYWRITE DWordString, [DEC Result, DEC4 Remains, 0]
    ELSE
        ARRAYWRITE DWordString, [DEC Remains, 0]
    ENDIF

[amgen]

Is it possible to describe the method or algorithm to get the decimal from the possible 8 hexadecimal of 32 bit number.... the conversion itself is pretty straight forward but the 8 bit manipulations are confusing...
.
.

[richard]

Just wanted to thank you once again

No problem Henrik glad you could make it work for you. its good to exercise the grey matter occasionally



@amgen

the conversion itself is pretty straight forward but the 8 bit manipulations are confusing...

to which 8bit manipulations do you refer ?

[Jerson]

Is it possible to describe the method or algorithm to get the decimal from the possible 8 hexadecimal of 32 bit number.... the conversion itself is pretty straight forward but the 8 bit manipulations are confusing...
.
.Attachment 9870

Consider this code.

dim array[8] as byte                        ' your hex bytes ($00-$0F) are input here from MSN to LSNibble
decimal  as long                             ' 32 bit value

     decimal = 0
     for i = 0 to 7
           decimal = decimal * 16             ' nibble max value is 16, so multiply the existing value by 16 to move decimal value one nibble to the left
           decimal = decimal + array[i]     ' add in the new nibble
     next
     
     ' at this point, decimal contains the converted value of the hex digits

Is this what you're looking for?