Re: 2nd hardware UART
I was going to say that you need to unlock the PPS before trying to configuring it but reading the datasheet it looks like it is unlocked at POR - I've always thought it was the other way around.
Anyway, here's the relevant parts from a project of mine which uses both UARTS, in this particular case I even use the PPS peripheral to switch UART2 pins around to two different devices. Using HSEROUT / HSEROUT2 in the code it worked out fine. This is for a 67K40 so it won't match your setup but perhaps it can provide some pointers./Henrik.Code:'---------------------------------------------------- ' PPS Unlock PPSLOCK = $55 PPSLOCK = $AA @ BCF PPSLOCK, PPSLOCKED RC6PPS = $0C ' We want PORTC.6 as EUSART1 TX RX1PPS = %00010111 ' We want PORTC.7 as EUSART1 RX RG7PPS = $0E ' We want EUSART2 TX on PortG.7 RX2PPS = %00110010 ' We want EUSART2 RX on PortG.2 ' Since we're switching UART pins around during runtime we need to leave the PPS lock open. 'PPSLOCK = $55 'PPSLOCK = $AA '@ BSF PPSLOCK, PPSLOCKED '---------------------------------------------------- ANSELA = %00110000 ' RA4, 5 analog, rest digital ANSELB = 0 ANSELD = 0 ANSELE = 0 ANSELF = 0 ANSELG = 0 ' Setup for EUSART1 RCSTA1 = $90 ' Enable serial port & continuous receive TXSTA1 = $24 ' Enable transmit, BRGH = 1 SPBRG1 = 64 ' 19200 Baud @ 64MHz, 0,04% SPBRGH1 = 3 BAUDCON1.3 = 1 ' Enable 16 bit baudrate generator ' Setup for EUSART2 RCSTA2 = $90 ' Enable serial port & continuous receive TXSTA2 = $24 ' Enable transmit, BRGH = 1 SPBRG2 = 138 ' 115200 Baud @ 64MHz, -0,08% SPBRGH2 = 0 BAUDCON2.3 = 1 ' Enable 16 bit baudrate generator TRISC.6 = 0 ' UART1 TX TRISC.7 = 1 ' UART1 RX TRISG.7 = 0 ' UART2 TX TRISG.2 = 1 ' UART2 RX
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