I didnt do that - as you can see PARK for example - pin 15 - is the output of pin 16 when pin 1 is high. 15 is basically floating when not activated - I want the pin on the PIC to be active high - not low. I think adding a high ohm resistor to ground will take care of it. Unless you have another idea?
I could have used a simple voltage divider as the input - but the input voltages could exceed the divider output (<5V) and I thought the opto would do the trick passing 5V(VCC) which is regulated.
Any way to paste a screen shot instead of a pdf?
https://optoelectronics.liteon.com/u...is%20Mar17.PDF - opto pinout
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