So if output is 11, then it will be 3+3+3+2
8=3+3+2
9=3+3+3
10+3+3+3+1
11=3+3+3+2
12=3+3+3+3
But these are sub-routines, which already include other statement, s so 3 here is actually doing 1+2+3, 2 is doing 1+2, and 1 is doing just 1![]()
So if output is 11, then it will be 3+3+3+2
8=3+3+2
9=3+3+3
10+3+3+3+1
11=3+3+3+2
12=3+3+3+3
But these are sub-routines, which already include other statement, s so 3 here is actually doing 1+2+3, 2 is doing 1+2, and 1 is doing just 1![]()
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