USB Receiving a Word

[sinoteq]

Hi,
Have you thought about that 1000 DEC is HighByte=3 and LowByte=232 and not 10 00?
What you get is actually correct if you look at following:

00001010 00000000=2560 HighByte=10 DEC LowByte=0
00000011 11101000=1000 HighByte=3 DEC LowByte=232

My suggestion is to split the word in VB using a different method.

[sean-h]

Ah now I see of course.

So in my VB prog I will take the value say 1000

Splt it down to 16bits
0000001111101000

Split again to high and low 8 bits

00000011 = 3
11101000 =232

Then send dec value of each set of 8 bits.

Excellent!

Regards

Sean.