SHIFTOUT MSB/LSBFIRST clarification

[peterdeco1]

I haven't done this in a long time but here is a snippet of code I used to send by SPI to a device:

Low PORTA.3 : Pause 10 'CHIP SELECT
ShiftOut PORTC.5,PORTC.3,0,[9254\16] 'playconfig0
ShiftOut PORTC.5,PORTC.3,0,[114\8] '1st play byte
High PORTA.3 : Pause 10 'deselect - end of word

The 0 after portc.3 means send code LSB. A 1 would send it MSB.

[iw2fvo]

thanks a lot,
Is your SPI device set to receive MSBfirst or LSBfirst please ?
Bye

[richard]

time on a scope flows from left to right

[iw2fvo]

I am so sorry Richard:
if the time flows from left to right, then the first bit sent should be on the right and not to the left of the scope !
Where am I wrong please ?
Bye

[richard]

which second was recorded first in time sequence ?

[richard]

slow your timbase right down , what direction does the dot travel

the dot having writ moves on

[iw2fvo]

the first bit sent out by the pic should be on the right ( 9 seconds old )
The last bit sent by the pic should be on the left ( 0 seconds old )

I am sorry for not understanding...
thanks

[iw2fvo]

thanks again,
I am sorry for not understand...
If I slow down the scope time base the dot goes from left to right.
So the first bit transmitted by the PIC is always to the right of the scope and the last transmitted by the PIC is shown to the left.
Am I right ?
Then the 9 seconds old bit is the first transmitted by the PIC.
The 0 secs old bit is the last transmitted by the PIC.
Is it right ?
Thanks