Yes, OK. But from 6 bytes you went to 3 words. Cannot understand the calculation you did.

;@ db 0x0E,0x10,0x1C,0x10,0x10,0x0E; // Code for char num 51 "3"
@ dw 0x80e,0xe10,0x710

0E=00001110, 10=00010000 and all these makes 80E?

Ioannis