Hi Guys,
I was involved in a coding challenge to calculate 2 pi r,
the circumference of a circle, given the radius as input, without any multiplication, division, or floats,
so I pretended I was using an 8 bit pic It was done in C, but all variables were integers,
so hopefully this BASIC is a good representation. (only the C was tested).
Cheers

Code:
   var word input = 300 ‘ input radius
    var byte twopi[19] = { 0x00,0x00,0x00,0x06,0x02,0x08,0x03,0x01,0x08,0x05,0x03,0x00,0x07,0x01,0x07,0x09,0x05,0x09,0x00 }
    var byte otput[19] = { 0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00 }
    var word adcnt = 0 ‘ counter
    var byte dgcnt = 0 ‘ digit index
    var byte carry = 0 ‘ carry digit


    while (adcnt < input)  ‘ multiply through addition
        dgcnt = 17 : carry = 0
        while (dgcnt > 0) ‘ cycle the digits
        	otput[dgcnt] = otput[dgcnt] + twopi[dgcnt] + carry : carry = 0 ‘ add digit
          	if (otput[dgcnt] > 9)
 		otput[dgcnt] = otput[dgcnt] - 10 : carry = 1
 		endif ‘ carry digit
            dgcnt = dgcnt - 1
        wend ‘ dgcnt
        if (carry != 0)
		otput[dgcnt] = otput[dgcnt] + 1
	endif
        adcnt = adcnt + 1	
	wend ‘ adcnt
    twopi[18] = 0 // terminate string

    // answer: 1884.9555921538758 is the string in the otput array