No pin on a PIC should be at a higher potential than Vdd, and certainly NOT highter than the max rating in the Datasheet (which is usually around 5.5v). Some PICs are rated to run to 12v. Check the Datasheet.
No pin on a PIC should be at a higher potential than Vdd, and certainly NOT highter than the max rating in the Datasheet (which is usually around 5.5v). Some PICs are rated to run to 12v. Check the Datasheet.
I have been looking around, and it seems like I am allowed to put a higher voltage on pin RA4. Copy-paste from datasheet:
I am using the PIC at 5V, so I thought that voltage on any pin would be Vdd + 0.3V, so that would be 5.3V max.Code:Absolute Maximum Ratings † Voltage on any pin with respect to VSS (except VDD, MCLR. and RA4) ... -0.3V to (VDD + 0.3V) Voltage on VDD with respect to VSS ................... -0.3 to +7.5V Voltage on MCLR with respect to VSS (Note 2) ........0 to +13.25V Voltage on RA4 with respect to Vss .......................0 to +8.5V
The line about RA4 simply says 0 to +8.5V, so I assume that I am allowed to sink 25mA's max at 8.5V max since I am using RA4 as an Open Drain output.
So this would leave me with the problem that I don't know whether I am allowed to connect the buzzer directly to 7.2V, and whether it will fry my PIC whenn Vdd is switched off? Also, am I getting the first part right?
Hi, Buzz
Why not use a stupid N Mosfet ( 2N7000 or BS 170 ) to switch your Buzzer ???
It would provide all the insulation you need ...
just invert your output level ( better for Power-on response of the Buzzer... hmmmm ? ) or use a P-Mosfet ( BS 250 ) and buzzer between Drain and ground ...
Alain
PS : 13v ... doesn't make you remember something about programming your PIC ??? ... jam at sight !!!
Last edited by Acetronics2; - 1st September 2005 at 08:27.
Yes, a stupid mosfet or even a cheap ass transistor could be the solution. Problem is, that I already have a PCB, and even with redesign really no space for extra components, not even a TO92...
So that's why I would like to fix this with just a piece of wire between the (now unused) pin RA4 and the buzzer.
Never soldered some components on your copper tracks and played with the cutter ??? ...
Time to learn !!!
Alain
PS: why not put your "piece of wire" to the 5v instead of 7v2 ??? just a track to cut ...
5v Buzzers also exist !!!
Last edited by Acetronics2; - 1st September 2005 at 08:41.
Normally, I would agree with you. I am very familiar with cutting traces and stuff (built several ground-planed spiderweb transmitters and so on). Problem is, that this design is already completed, several PCB's have been made, and I wouldn't like to rework them all with cutting traces and stuff. Feeding the buzzer with 5V gives me too much sound-loss.
I know I am starting to be a pain in the ass, but the solution like in my opening post would suit me best. I think I am going to sacrifice a PIC, and just see what happens. The 7.2V voltage probably wont't be the problem, the only thing I am afraid of, is that the PIC might not like the 7.2V being present when the Vdd-voltage regulator is switched off. I'll just see what happens, if it fries my PIC, I probably cannot bypass the extra FET-idea...
edit: unfortunately 5V buzzers are too "quiet". I ordered like 7 or 8 different types, but I didn't like any of them...
...my demands are just way too high...![]()
Last edited by Buzzz; - 1st September 2005 at 08:51.
All this effort for nothing...
The buzzer appears to draw just over 30 mA's of current, even at 5V. So I will need a tranistor/fet anyways. So thanks for all your help, I am going to "spiderize" my PCB's....![]()
Take a look at these http://www.mallory-sonalert.com/cata...lert_index.htmOriginally Posted by Buzzz
The've got a whole bunch of sounds, and all the 5 volt ones will run directly from RA4 - no diodes, no hacking, no popped PICs.
Bookmarks