bit 7 = 128 =$80May I kindly ask you to explain how you found out those values please?
Code:hex dec row1 dram address = 0 0 128 + 0 = 128 = $80 row2 dram address = $10 16 128 +16 = 144 = $90 row3 dram address = $20 32 128 +32 = 160 = $A0
bit 7 = 128 =$80May I kindly ask you to explain how you found out those values please?
Code:hex dec row1 dram address = 0 0 128 + 0 = 128 = $80 row2 dram address = $10 16 128 +16 = 144 = $90 row3 dram address = $20 32 128 +32 = 160 = $A0
Last edited by richard; - 9th August 2016 at 00:03. Reason: white space
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