bit order inverting

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  1. - 27th July 2005, 16:38 #2
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    mister_e
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    in a loop.. well i guess.
    Code:
    for BitToShift=0 to 7
    FinalVar.0[7-BitToShift]=InitialVar.0[BitToShift]
    next
    There's probably a tons of way but this is the first who comes..
    Last edited by mister_e; - 27th July 2005 at 16:41.
    Steve

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