Quote Originally Posted by Jerson View Post

Assuming you want a 0.1 deg resolution, I would do this (keep in mind the largest value that Temp can hold. Temp*1000 will define the limit of temperature going into the routine)
Temp = (Temp*1000)/Cook_Adjust (max input temp is now 65 since 65*1000 approximately fills the 16b integer)
You could also do this
Temp = (Temp*100) / (Cook_Adjust / 10) (max input temp is 650. However, cook_adjust should be multiples of 10 to impact the calculations)

Now, convert to F
Temp = Temp + (Temp << 3) ' mul by 9 x + 8*x = 9x
Temp = Temp / 5 ' div by 5
Temp = Temp + (32*10) ' add 32 with 1 decimal accounted for

and display it by splitting the value thus
Display Temp / 10, ".", Temp MOD 10

You need to specify your input range to make this technique practical for you.
Well then, that seems a LOT easier now that I've had time to look at it. I'm going to use longs so that my max temp will fit and do the * 1000.

Thanks for the help!