I never used a current transformer but I suggest you place the burden resistor before the bridge.

Then you CT is 100:50 = 20:1

@100A on the primary you'll have 5 amps on the secondary, so 2ohms will give you 10VAC rms.

The bridge has a 1.4V drop you must take in account. Also, AC voltage fully rectified with a capacitor and no load will give you a peak voltage of (v * 1.4142) (1.4142 = square root 2).

So for a 10VDC max:

(10/1.4142) + 1.4 = 8.47VAC on the secondary.

8.47VAC / 5A = 1.694 ohm. Good luck to find one.

My suggestion: pick a standard value < 1.694ohm and then compute the results. Finally, use a good multimeter to caliber your system.

HTH